I want to construct a 100mg/L of AgNO3 solution, how oodles Ag will be surrounded by that much stock?
Answers: Moles = mass / Molar Mass
To find out how many mols of Ag will be within 1L of your solution:
Calculate the Molar Mass of AgNO3
100/MM = number of moles of AgNO3 per L
This is the same as the number of moles of Ag per L
What is your starting stuff? Whatever it is, start off by matching the equation between that (in REACTANTS) and your AgNO3 (in PRODUCTS). Then use the value of your staring matter (either moles or mg) and utilize
grams->moles->moles->grams relationship
grams of starting converted into moles; mulitply that by the moles/gram of AgNO3; mulitply the mole(starting material) x moles (product); then convert moles of final product into grams of final product.
That's your process.
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