Plz aid me out on this ask...!?

Calculate the energy released (in KJ ) from the metabolism of 3.50 fluid of vodka that is to say 62.0% water and 38.0% ethanol by volume, assuming that the total volume is equal to the sum of the volume of the two components. The density of ethanol is 0.824 .


Answers:    First, metabolism is a hydrocarbon combustion rxn, so no carbon ... no liveliness (E). Put another way, (pure) marine has no caloric good point, so you can safely do away with the water and digit out the mass of EtOH like so:

.38 X volume (ml) X density (g/ml).

3.50 ml? dL? L? -- check your homework examine to find out what units you're given (otherwise the query makes no sense).

Now you enjoy a mass of hydrocarbon, right?

You know E = mc^2

Look up c (it's a constant with unit of m/s)

Mass (m) needs to be within kg for the mass–energy equivalence formula, and "E" is in joules (units m^2 X kg / s^2), so the answer you seize needs to be converted to kJ.
flattery !
E=mc*2 is einsteins rule! where c is the speed of pale!
the question is missing something
Aiden is undeniably correct (but he almost provided too much info. and gave away the answer). E=mc2 is applicable to this cross-question. Just because it contains the constant "c" (the velocity of light within a vacuum) is no reason not to apply the formula when the desired answer is contained by units of E!!

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